Answer:
From the sample of n= 200 people,
The proportion of people with kids is:
p'= 110/200= 0.55
The confidence interval for population proportion is given by:
[tex]p' - Z_{\alpha /2} \sqrt[]{\frac{p'(1-p')}{n} } } \leq P\leq p' + Z_{\alpha /2}\sqrt[]{\frac{p'(1-p')}{n} } }[/tex]
[tex]= p' - Z_{\alpha /2} \sqrt[]{\frac{0.55(0.45)}{200} } } \leq P \le p' + Z_{\alpha /2} \sqrt[]{\frac{0.55(0.45)}{200} } }[/tex]
[tex]= p' - Z_{\alpha /2} 0.0352} } } \leq P\le p' + Z_{\alpha /2} 0.0352} }[/tex]
Where P is the population proportion and Z is the critical value at a given level of significance α.
