Answer:
0.9972 fraction of plutonium will remain after 100 years.
Explanation:
Half life of plutonium = [tex]t_{1/2}=25000 years[/tex]
Let the initial mass of plutonium be = [tex]A_o[/tex]
Mass of plutonium after time of 100 years = A
Decay constant for this process = [tex]\lambda =\frac{0.693}{t_{1/2}}[/tex]
[tex]A=A_o\times e^{-\lambda t}[/tex]
[tex]A=A_o\times e^{-\frac{0.693}{25000 years}\times 100 year}[/tex]
[tex]A=A_o\times 0.9972[/tex]
[tex]\frac{A}{A_o}=0.9972[/tex]
0.9972 × 100 = 99.72 %
0.9972 fraction of plutonium will remain after 100 years.
