Given f(x)= a×e−bx , where a = 1 and b = 6,
calculate g(x)=dfdx and obtain g(1) (that is, evaluate the derivative of f(x) at x = 1).
Report your answer with three significant figures.

Question

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Respuesta :

ChiKesselman ChiKesselman · Answer 1 · 2020-01-27T05:02:40+01:00

Answer:

g(1) = -0.015

Step-by-step explanation:

We are given he following in the question:

[tex]f(x) = ae^{-bx}[/tex]

For a = 1 and b = 6, we have,

[tex]f(x) = e^{-6x}[/tex]

We have to find the the derivative of f(x) with respect to x.

[tex]g(x) = \dfrac{d(f(x))}{dx} = \dfrac{d(e^{-6x})}{dx}\\\\g(x) = -6e^{-6x}\\\\g(1) = \dfrac{d(f(x))}{dx}\bigg|_{x=1} = -6e^{-6} = -0.015[/tex]

Thus, g(1) = -0.015