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The velocity at [tex]t_0 = 3\; seconds[/tex] is 12.33 m/s.

Given the following data:

  • [tex]x(t) = 4t^2 + 1[/tex]
  • [tex]t_0 = 3\; seconds[/tex]

To find the velocity at the given time:

In this exercise, you are required to find the velocity of an object moving along a coordinate line.

Therefore, we would substitute the value of the time into position-time equation, so as to determine its distance.

Substituting the given value into the formula, we have;

[tex]\\x(3) = 4(3)^2 + 1\\\\x(3) = 4(9) + 1\\\\x(3) = 36 + 1\\\\x(3) = 37 \; meters[/tex]

Now, we can solve for the velocity by using the formula;

[tex]Velocity = \frac{Distance}{Time} \\\\Velocity = \frac{37}{3}[/tex]

Velocity = 12.33 m/s

Therefore, the velocity at [tex]t_0 = 3\; seconds[/tex] is 12.33 m/s.

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