Respuesta :
Answer:
35 pounds is the point estimate for the the number of excess pounds that population weighed.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 90
Sample mean, [tex]\bar{x}[/tex] = 35 pounds
Population standard deviation, [tex]\sigma[/tex] = 3.5
We have to find the point estimate of the number of excess pounds that population weighed.
The best point estimate is the sample mean.
Thus, we can write,
[tex]\bar{x} = \mu = 35[/tex]
Thus, 35 pounds is the point estimate for the the number of excess pounds that population weighed.
Answer:
The point estimate for the number of excess pounds that the population weighed is 30 pounds.
Explanation:
Given:
Sample size, n [tex]= 90[/tex]
The sample mean [tex]$(\overline{\mathrm{x}})$[/tex] [tex]=35[/tex] pounds
Population standard deviation [tex]= 3.5[/tex]
To find the best point estimate of the number of excess pounds:
- The Point estimate of the population mean, [tex]$\mu$[/tex] is the Sample mean [tex]$(\overline{\mathrm{x}})$[/tex]
- A Population Mean is not an instance of a point estimate whereas a Sample Mean is an instance of a point estimate.
By the definition, we can write
[tex]$(\overline{\mathrm{x}})$[/tex] [tex]=35[/tex] pounds [tex]=$\mu$[/tex]
Therefore, The best point estimate for the number of excess pounds that the population weighed is 30 pounds.
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