Answer:
[tex](4,2)[/tex]
Step-by-step explanation:
We have been given that triangle HIJ has coordinates [tex]H(-1,1)[/tex], [tex]I(1,4)[/tex] and [tex]J(1,3)[/tex]. We are asked to find the coordinate of point I after a translation of 3 units to the right and 2 units down.
The translation of 3 units to right means that we need to add 3 to x-coordinates.
The translation of 2 units down means that we need to subtract 2 from y-coordinates.
[tex]H(-1,1)\rightarrow H'(-1+3,1-2)=H'(2,-1)[/tex]
[tex]I(1,4)\rightarrow I'(1+3,4-2)=I'(4,2)[/tex]
[tex]J(1,3)\rightarrow J'(1+3,3-2)=I'(4,1)[/tex]
Therefore, the coordinates of point I' after translation would be [tex](4,2)[/tex].
