Respuesta :
The required length is 5.8 ft and the width is 1.84 ft
Let the width of the rectangle is x
Then the length of the rectangle is [tex]3\frac{1}{6}x=\frac{19x}{6}[/tex]
The perimeter of the rectangle is [tex]15\frac{1}{3}[/tex] cm
Then,
[tex]2(l+b)=\frac{46}{3}\\ 2(x+\frac{19x}{6})=\frac{46}{3} \\ 2(\frac{25x}{6})= \frac{46}{3}\\x=1.84[/tex]
Then length=[tex]\frac{19(1.84}{6}) =5.8 ft[/tex]
And width=1.84 ft
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