An atom of a particular element is traveling at 1.00% of the speed of light. The de Broglie wavelength is found to be 3.31 × 10-3 pm. Which element is this? Prove it.

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Neetoo

Answer:

The given atom is of Ca.

Explanation:

Given data:

Speed of atom = 1% of speed of light

De-broglie wavelength = 3.31×10⁻³ pm (3.31×10⁻³ / 10¹² = 3.31×10⁻¹⁵ m)

What is element = ?

Solution:

Formula:

m = h/λv

m = mass of particle

h  = planks constant

v = speed of particle

λ = wavelength

Now we will put the values in formula.

m = h/λv

m = 6.63×10⁻³⁴kg. m².s⁻¹/3.31×10⁻¹⁵ m ×( 1/100)×3×10⁸ m/s

m = 6.63×10⁻³⁴kg. m².s⁻¹/ 0.099×10⁻⁷m²/s

m = 66.97×10⁻²⁷ Kg/atom

or

6.69×10⁻²⁶ Kg/atom

Now here we will use the Avogadro number.

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

Now in given problem,

6.69×10⁻²⁶ Kg/atom × 6.022 × 10²³ atoms/ mol × 1000 g/ 1kg

40.3×10⁻³×10³g/mol

40.3  g/mol

So the given atom is of Ca.

The movement of sounds, in the same manner, is called wavelength.

The correct element is Ca.

The data in the question is as follows:-

  • Speed of atom is 1% of the speed of light
  • De-Broglie wavelength = [tex]3.31*10^{-3}\\\\\frac{(3.31*10^{-3}}{10^{12}}\\ = 3.31*10^{-15} m[/tex]

The formula we will used is [tex]m = \frac{h}{λv}[/tex]

The data is given is as follows:-

  • m = mass of the particle
  • h  = planks constant
  • v = speed of particle
  • λ = wavelength

Now we will put the values in the formula and solve the equation.

[tex]m = \frac{6.63*10^{-34}}{3.31*10^{-15} ( \frac{1}{100})*3*10^8}[/tex]

After solving the value of m is[tex]66.97*10^{-27}[/tex]

Now in the given problem, the solution is as follows:-

[tex]6.69*10^{-26}* 6.022 * 10^{23} * 1000[/tex]

After solving the equation the answer is 40.3

Hence, the 40.3 is the mass of calcium.

For more information, refer to the link:-

https://brainly.com/question/22810476