Respuesta :
Answer:
a) 4.95 s
b) 7.00 s
c) 4.95 s
d) 9.9 s
Explanation:
The equation for the period of the object is
T=2×π×[tex]\sqrt{m/k}[/tex] =[tex]T_{0}[/tex]=7.0 s............................(1)
m= mass of the object
k= spring constant
For part (a)
m=[tex]\frac1{2}[/tex]
putting the value of m in equation (1)
T=4.95 s
For part (b)
the period does not depends on amplitude therefore
T=7.00 s
For part (c)
spring constant=2k
putting the value of spring constant in equation (1)
T=4.95 s
For part (d)
m= 2
putting the value of m in equation (1)
T=9.9 s
a) 4.95 s when the mass is halved
b) 7.00 s when the amplitude is doubled
c) 4.95 s when spring constant is doubled
d) 9.9 s when mass is doubled
Given:
T₀=7.0 s
The equation for the time period of the object is
[tex]T=2*\pi *\sqrt{\frac{m}{k} }[/tex] ......................(i)
where m= mass of an object and k= spring constant
- For solving a.
m= 1/2
∵T=7.0 s
On substituting value in equation (i)
Thus, T=4.95 s
- For solving b.
Time period does not depend on amplitude thus,
T=7.0 s
- For solving c.
Spring constant, k=2k
On substituting value in equation (i)
Thus, T=4.95 s
- For solving d.
Mass=2m
On substituting value in equation (i)
Thus, T=9.9 s
Learn more:
brainly.com/question/3613222
