Answer:
change interval is 3.93 sec
clearance interval is 1.477 sec
Explanation:
Given data:
upgrade of intersection 4%
street total width at intersection is 60 ft
vehicle length of approaching traffic = 16 ft
speed of approaching traffic =40 mi/hr
85th percentile speed is calculated as
S_{85} = S +5
S_{ 85} = 40 + 5 = 45 mi/h
15th Percentile speed
[tex]S_{15} =S-5[/tex]
= 40 - 5 = 35 mi/hr
change in interval is calculated as
[tex]y = t + \frac{1.47 S_{85}}{2a +(64.4\times 0.01 G}[/tex]
t is reaction time is 1.0,
deceleration rate is given as 10 ft/s^2
[tex]y = 1.0 +\frac{1.47\times 45}{2a +(64.4\times 0.01\times 4}[/tex]
y = 3.93 s
clearance interval is calculated as
[tex]a_r = \frac{W+ L}{1.47\times S_{15}}[/tex]
[tex]a_r = \frac{60+16}{1.47\times 35} = 1.477 s[/tex]
