Answer:
m will be equal to 1158.73 gram
Explanation:
We have given mass m when frequency is 0.83 Hz
So mass [tex]m_1=m[/tex] and frequency [tex]f_!=f[/tex] let spring constant of the spring is KK
Frequency of oscillation of spring is given by [tex]f=\frac{1}{2 \pi }\sqrt{\frac{k}{m}}[/tex]
From above relation we can say that [tex]{\frac{f_1}{f_2}}=\sqrt{\frac{m_2}{m_1}}[/tex]
It is given that when an additional 730 gram is added to m then frequency become 0.65 Hz , [tex]f_2=0.65Hz[/tex]
So [tex]m_2=m+730[/tex]
So [tex]\frac{0.93}{0.65}=\sqrt{\frac{m+730}{m}}[/tex]
[tex]\frac{m+730}{m}=1.63[/tex]
[tex]0.63m=730[/tex]
m= 1158.73 gram
