Respuesta :
The question is incomplete, here is the complete question:
A solution is prepared at 25°C that is initially 0.075 M in chlorous acid [tex](HClO_2)[/tex] , a weak acid with [tex]K_a=1.1\times 10^{-2}[/tex], and 0.34 M in potassium chloride [tex](KClO_2)[/tex] . Calculate the pH of the solution. Round your answer to 2 decimal places.
Answer: The pH of the solution is 2.62
Explanation:
The chemical equation for the reaction of chlorous acid and potassium hydroxide follows:
[tex]HClO_2+KOH\rightarrow KClO_2+H_2O[/tex]
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
[tex]pH=pK_a+\log(\frac{[salt]}{[acid]})[/tex]
[tex]pH=pK_a+\log(\frac{[NaHCO_3]}{[H_2CO_3]})[/tex]
We are given:
[tex]pK_a[/tex] = negative logarithm of acid dissociation constant of chlorous acid = 1.96
[tex][KClO_2]=0.34M[/tex]
[tex][HClO_2]=0.075M[/tex]
pH = ?
Putting values in above equation, we get:
[tex]pH=1.96+\log(\frac{0.34}{0.075})\\\\pH=2.62[/tex]
Hence, the pH of the solution is 2.62