Explanation:
It is given that the value of P is 1110 N. And, for pin connection we have only two connections which are [tex]A_{x}[/tex] and [tex]A_{y}[/tex]. Let T be the tension is rope.
So, [tex]\sum F_{y} = 0[/tex] and [tex]A_{y}[/tex] - 1110 = 0
[tex]A_{y} = 1110 N[/tex]
[tex]\sum F_{x}[/tex] = 0
And, [tex]T - A_{x}[/tex] = 0
T = [tex]A_{x}[/tex]
Also, [tex]\sum M_{A}[/tex] = 0
1110(0.75 + 0.75 + 0.75) - T(0.5 + 0.1) = 0
2497.5 - 0.6T = 0
T = 4162.5 N
= 4.16 kN
Therefore, we can conclude that the tension in the rope if the frame is in equilibrium is 4.16 kN.
