Answer:
v = 3.06 x 10⁻³ m/s
Explanation:
given,
mass of man,M = 90 kg
mass of stone , m= 69 g = 0.069 Kg
speed of the stone, u = 4 m/s
speed of the man, v = ?
using conservation of momentum
initial velocity of the man and stone is equal to zero
(M + m)V = M v + m u
(M + m) x 0 = 90 x v + 0.069 x 4
90 v = 0.276
v = 0.00306 m/s
v = 3.06 x 10⁻³ m/s
speed of the man on the frictionless surface is equal to 3.06 x 10⁻³ m/s
