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A batch chemical reactor achieves a reduction in concentration of compound A from 90 mg/l to 10 mg/L in one hour. if the reaction is known to follow zero order kinetics, determine the value of the rate constant in (mg/L.hr) unit.

Respuesta :

Answer:

value of the rate constant is 80 mg/L-hr

Explanation:

given data

concentration of compound Cao = 90 mg/l

Ca = 10 mg/L

time = 1 hour

solution

we use here  zero order reaction rate flow

-rA = K Ca

[tex]\frac{-dCa}{dt}[/tex] = K

-d Ca = k dt

now we will integrate it on the both side by Cao to ca we get

[tex]- \int\limits^{Ca}_{Cao} {dCa} \, = K \int\limits^4_0 {dt} \,[/tex]  

solve it we get

cao - Ca = K t

put here value  and we get K

90 - 10 = K 1

K = 80 mg/L-hr

so value of the rate constant is 80 mg/L-hr

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