Answer:
Step-by-step explanation:
Given that taxi Fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.
For a random single taxi std deviation is 2.20
But for a sample of size 10, std deviation would be
[tex]\frac{2.20}{\sqrt{10} }[/tex]
This would be less than the 2.20
Because std devition is less for sample we get a big z score for the sample than the single.
As positive values of z increase we find that probability would decrease since normal curve is bell shaped.
So single taxi fare would have higher probability than sample.
B) Here >24.
By the same argument we have z value less for single taxi hence the probability for more than that would be less than that of sample size 10
