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A 1300 kgkg car drives around a flat 200-mm-diameter circular track at 40 m/sm/s . Part A What is the magnitude of the net force on the car? Express your answer to two significant figures and include the appropriate units. FnetFnet = nothingnothing

Respuesta :

Answer:

[tex]F_C=20800\ N[/tex]

Explanation:

Given:

  • mass of the car, [tex]m=1300\ kg[/tex]
  • diameter of the track, [tex]d=200\ m[/tex]
  • speed of the car, [tex]v=40\ m.s^{-1}[/tex]

During the motion of the car on a flat circular track there acts a force which pushes the car inwards to comply in the circular motion. This force is called centripetal force which is generated due to the frictional force between the road and the tyres of the car.

This centripetal force is given as:

[tex]F_C=m.\frac{v^2}{r}[/tex]

here: r = radius of the track = [tex]\frac{d}{2}[/tex]

[tex]F_C=1300\times \frac{40^2}{100}[/tex]

[tex]F_C=20800\ N[/tex] is the force which makes the car turn inwards going with the given uniform speed.