*plz help it’s due tomorrow:)
The graph shows the temperature,y, in a freezer x minutues after it was turned on. Five minutes after being turned on, the temperature was actually three degrees from what the trend line shows. What values could the actual temperature be after the freezer was on for five minutes?

First, you must find the y-value returned by the line in the graph for a time (x) of five minutes, and then use the deviation of 3º to conclude the range of the real temperature.

1. y- value at x = 5 min.

The trend line (blue line in the graph) passes through the point (5,15), which means that it predicts a temperature of 15ºF when the time (x) is 5 minutes, or five minutes after the freezer was turned on.

2. Actual temperature value

It is stated that the temperature was actually three degrees from what the trend line shows, that means that the actual temperature could be 3ºF more or 3ºF less than the predicted temperature of 15ºF.

Mathematically:

Temperature = 15ºF ± 3ºF

Temparature = 15ºF + 3ºF or 15ºF - 3ºF

Temperature = 18ºF or 12ºF ← answer.

darkskydrops darkskydrops · Answer 2 · 2021-02-10T15:42:32+01:00

darkskydrops darkskydrops

10-02-2021

Answer:what would be the slope what would it represent in this situation same with the y intercept what it represents and the equation

Step-by-step explanation:

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