Respuesta :
The number of ⁶Li atoms present is 1.23 × 10²⁴ atoms
Stoichiometry
From the question, we are to determine the number of ⁶Li atoms present.
First, we will determine the number of moles of ⁶Li present.
Using the formula,
[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass}[/tex]
Mass of ⁶Li = 12.3 g
Molar mass of ⁶Li = 6 g/mole
Number of moles of ⁶Li present = [tex]\frac{12.3}{6}[/tex]
Number of moles of ⁶Li present = 2.05 moles
Now, for the number of atoms
Using the formula,
Number of atoms = Number of moles × Avogadro's constant
Then
Number of atoms of ⁶Li = 2.05 × 6.022×10²³
Number of atoms of ⁶Li = 1.23451 × 10²⁴ atoms
Number of atoms of ⁶Li ≅ 1.23 × 10²⁴ atoms
Hence, the number of ⁶Li atoms present is 1.23 × 10²⁴ atoms
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