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If it takes 38.70cm³ of 1.90 M NaOH to neutralize 10.30cm³ of H2SO4 in a battery, What's the Molarity of the H2SO4 ?​

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Eduard22sly

Answer: 3.57M

Explanation:Please see attachment for explanation

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bigdammy2013

Answer:

Volume of acid Va = 38.70cm3,

Concentration of acid Ca = 1.90M

Volume of Base Vb = 10.30cm3

Concentration of base Cb = ?

Equation of the reaction

H2SO4 + 2NaOH = Na2SO4 + 2H2O

No of mole of acid Na = 1

No of mole of base Nb = 2

CaVa/CbVb = Na/Nb

Cb = CaVaNb/VbNa

Cb = 1.9*38.7*2/10.30*1

Cb = 14.2777M

Explanation:

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