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An electric field from a charge has a magnitude of 4.5 × 104 N/C at a certain location that points inward. If another charge with a magnitude of −2.0 × 10−6 C is brought near it, what is the strength of the electrostatic force that acts on this charge and how do the two charges behave?

0.09 N; repel each other
−0.09 N; attract each other
−2.3 N; repel each other
2.3 N; attract each other

Respuesta :

jimohfawwazajibola25

Answer:

−0.09 N; attract each other

Explanation:

E = F/Q

F = E x Q

  = 4.5 × 104 x (−2.0 × 10−6)

   = - 0.09N

Inward charges means the charges are positive. so the charge in this context is positive. Like charges repel unlike charges attract

The two charges repel each other and the electrostatic force on the second charge is 0.09N

Electrostatic force:

Let us consider the charge [tex]Q_1[/tex] has an electric field [tex]E_1=4.5\times10^4 N/C[/tex]

and the charge [tex]Q_2=-2.0\times10^{-6} C[/tex].

It is given that the electric field E₁ is pointed inwards the charge Q₁, so charge Q₁ must be negative.

So, if a charge [tex]Q_2=-2.0\times10^{-6} C[/tex] which is also negative is brought near the charge Q₁, then both the charges will repel each other.

The electrostatic force acting on the second charge is given by:

[tex]F=E_1Q_2\\\\F=4.5\times10^4\times(2.0)\times10^{-6} \\\\F=0.09N[/tex]

Learn more about electrostatic force:

https://brainly.com/question/9774180?referrer=searchResults

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