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Phillip departed from town A with coordinates (1, 6) towards town B with coordinates (7, 6). At the same time Bruce headed from town B to town A. What are the coordinates of point C where they will meet if Bruce is moving twice as fast as Phillip?

Respuesta :

Edufirst

Answer:

  • (3,6)

Explanation:

Since Bruce is moving twice as fast as Phillip, when they meet, Phillip will have moved x units while Bruce will have moved 2x units.

Thus, the distance from A to B will be split in a 1: 2 ratio.

1. Coordinate x of point  C:

  • Horizontal distance from A to B: 7 - 1 = 6
  • Divide 6 in three parts (1 + 2 = 3): 6 / 3 = 2
  • Phillip will have moved one part, equal to 2 units from (1,6), thus the x-coordinate will be 1 + 2 = 3 units

2. Coordinate y of point C:

  • Vertical distance from A to B: 6 - 6 = 0
  • That means that there is not movement in the vertical position (y-coordinate), thus the y-coordinate of the point C will be 6 units.

3. Answer:

The coordinates of point C where they will meet are (3,6).

The coordinates of point C where they will meet if Bruce is moving twice as fast as Phillip is (3,6).

  • The calculation is as follows:

Since Bruce is moving twice as fast as Phillip, when they meet,

Phillip will have moved x units while Bruce will have moved 2x units.

So,, the distance from A to B will be split in a 1: 2 ratio.

1. Coordinate x of point  C:

Horizontal distance from A to B: 7 - 1 = 6

Divide 6 in three parts (1 + 2 = 3): [tex]6 \div 3[/tex] = 2

Phillip will have moved one part, equal to 2 units from (1,6), thus the x-coordinate will be 1 + 2 = 3 units

2. Coordinate y of point C:

Vertical distance from A to B: 6 - 6 = 0

Learn more: https://brainly.com/question/7695753?referrer=searchResults

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