The amount of time it would take after the ball is kicked before it will hit the ground again is 2.5 seconds
The reason for the above time duration of the ball is presented as follows:
The known parameters of the ball kicked into the air are:
The time at which the ball is kicked into the air, t = 0
The equation that gives the height of the ball as a function of time, t, f(t), is presented as follows:
f(t) = -16·t² + 40·t
The required parameter:
The time it would take the ball to hit the ground
Method:
Equate the function for the height to zero, which is the height at ground level and solve for time, t as follows:
At ground level, we have:
h = f(t) = 0 = -16·t² + 40·t
Therefore, we get;
0 = -16·t² + 40·t
Factorizing gives;
0 = t × (-16·t + 40)
Therefore;
t = 0, or -16·t + 40 = 0
From which we have:
-16·t + 40 = 0
16·t = 40
t = 40/16 = 2.5
t = 2.5 seconds
The time it will take the ball to hit the ground after being kicked, t = 2.5 seconds
Learn more about time of flight of projectile motion here:
https://brainly.com/question/11315006
