Respuesta :
Since the specific heat of silver is given to be 0.057 calories/gram*C, obtaining the amount of calories should be as easy as multiplying the specific heat by the given values of the weight and the temperature to do unit cancellation. This is shown below:
(0.057 calories/gram*C)(10 grams)(20 C) = 11.4 calories
(0.057 calories/gram*C)(10 grams)(20 C) = 11.4 calories
Answer: 11.4 cal
Explanation:
The amount of heat absorbed by the sample is given by:
Q = m c ΔT
where, m is the mass, c is the specific heat and ΔT is the change in temperature.
Specific heat is the amount of heat required to raise the temperature of 1 g of mass by 1°C.
⇒Q = 10.0 g × 0.057 cal/g °C × 20.0° C = 11.4 cal
Thus, 11.4 calories would be absorbed by the sample of silver.