contestada

When p = 12, t = 2, and s=1/6r = 18. If r varies directly with p and inversely with the product of s and t, what is the constant of variation?

Respuesta :

olemakpadu
r α p/(st)

r =  kp/(st)

Where k = constant of proportionality

r = 18, p = 12, t = 2 , s = 1/6

r =  kp/(st)

18 =  k*12/((1/6)*2)

18 = 12k /(1/3)

18 = 12*3*k

18 = 36k

18/36 = k

1/2 = k

k = 1/2

Constant of variation = 1/2 = 0.5  


Ckaranja
r[tex] \alpha \frac{p}{st} [/tex]
r=k[tex] \frac{p}{st} [/tex]
18=12[tex] \frac{k}{1/6*2} [/tex]
18=12*3k
k=[tex] \frac{1}{2} [/tex]

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