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Which inequality will have a solid boundary line and a shaded region above its graph?


x − y ≥ 3



2x − 3y ≤ 3



3y − x < 2



2x + y < 7

Respuesta :

Mehek
A solid line means either ≥ or ≤

So either A or B
 
Above the graph: Must be greater than y

B

Answer:

B. 2x − 3y ≤ 3

Step-by-step explanation:

We are required to find the graph having solid boundary line.

When a graph have soled boundary line. Then, the inequality will have the equality sign in it.

That is, strict inequality can never have a solid boundary line.

So, option C and D are discarded.

Further, the graph must have shaded region above the graph.

Now, the region above the graph means that, the inequality must be of the form [tex]y > ax+b[/tex].

So, we have,

[tex]x-y\geq 3[/tex] implies [tex]y\leq x-3[/tex]

So, option A is not correct.

But, [tex]2x-3y\leq 3[/tex] implies [tex]y\geq \frac{2x}{3}-1[/tex]

Thus, the inequality having solid boundary and graph above is [tex]2x-3y\leq 3[/tex].

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