Suppose we have two identical boxes of matter, A and B, that are in thermal contact but cannot exchange materials. They come to thermal equilibrium. System 1 consists of box A alone, while system 2 consists of both boxes A and B. What can you say about the entropy of the two systems? Choose all correct answers.
a. The entropy of system 2 is twice as high as that of system 1.b. The entropy of system 2 is a lot more than twice as high compared to system 1.c. The number of microstates of system 2 is twice as high as those of system 1.d. The number of microstates of system 2 is a lot more than twice as high as those of system 1.e. You cant tell anything about the comparative entropy of the two systems without more information.

Given that both the boxes are in thermal equilibrium. This means that there is no energy exchange between the systems.
According to the second law of thermodynamics, we can say that the entropy of a thermally isolated system in equilibrium will be at a maximum and constant value.
As both the boxes are in thermal equilibrium, we can say that the entropy of system 1 and system 2 are equal.
But both systems can have a specific number of microstates.

System 1 = [tex]A[/tex]

System 2 = [tex]A+B[/tex]

Given that, both the boxes are identical.

So, the number of microscopic configurations for system 2 will be twice as much as that of system 2.

So, we can say that the number of microstates of system 2 is twice as high as those of system 1.

Learn more about entropy and microstates here:

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