105146 Pa
1) We will make a Free-Body Diagram representing all the upward and downward pressures exerted on the piston.
2) We will formulate an equation balancing all upward and downward pressures.
   P1= Patm + Pw + Pspring
3) We will calculate each of the pressures separately.
     P = F/A
     F= ks
     k= 38×1000 =38000 N m
     s= 2.5 /1000 = (2.5x10^-3) m
     F = 38000×(2.5x10^-3) = 95 N
     A = 30/10000 = (30x10^-4) m2
     P = 95 / (30x10^-4)
     Pspring ≅ 3167 Pa
     P = F/A
     F = W = mg
     W = 2×9.81 = 19.62 N
     A = 30/10000 = (30x10^-4) m2
     P = 19.62 / (30x10^-4)
     Pw = 654 Pa
    P = 1atm = 101325 Pa
    Patm = 101325 Pa
4) We will add all the downward pressures to reach the final answer (initial pressure inside the cylinder).
    P1= Patm + Pw + Pspring
    P1= 101325+654+3167
    P1= 105146 Pa