Answer:The standard reduction potential, Eo , for Pb2+(aq) is greater than that for Mg2+(aq).
Explanation:
Metals are usually arranged in an order of reactivity called activity series. Metals that are high up in the series are good reducing agents with very low (very negative) reduction potentials. Metals with greater (less negative) reduction potentials are found lower in the series. In the image attached, elements were arranged according to their reducing ability. Magnesium is very electro positive hence it is a better reducing agent with a lesser standard reduction potential than lead(refer to the image for numerical values of standard reduction potentials). Hence it displaces lead from solution and the elemental lead deposits on the wire.
The conclusion from the observation when a magnesium wire is dipped into a solution of lead (II) nitrate is;
(A) The standard reduction potential, E₀ , for Pb²⁺(aq) is greater than that for Mg²⁺ (aq).
In chemistry, there is what we call activity series for where elements are arranged in decreasing order of reactivity.
Now, in the activity series, metals that are high up in the series have low reduction potentials and as such are good reducing agents. Meanwhile, metals that have higher reduction potentials are not good reducing agents and are found at the bottom region of the activity series.
Since magnesium wire is dipped into a solution of lead (II) nitrate, we are dealing with two metals and from the activity series of elements online, the standard reduction potential of Pb²⁺(aq) is -0.13 V which is greater than that for Mg²⁺ (aq). which is -2.36 V.
Read more on Activity Series at; https://brainly.com/question/17469010
