Jack starts walking east ( x-direction) at a pace of 2 m/s. Jill, who is very upset with Jack, is running west (- x-direction) towards him at a rate of 4 m/s and is initially 200 meters to the east of Jack when she sees him. When and where does she run into him?

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CarliReifsteck CarliReifsteck · Answer 1 · 2020-02-22T08:25:05+01:00

Answer:

Jill will ran into jack after 33.33 sec.

The distance traveled by Jack in 33.33 seconds is 66.67 m.

Explanation:

Given that,

Speed in x direction= 2 m/s

Distance = 200 m

Rate = 4 m/s

Let after t seconds, she will run into him.

Therefore, total displacement of Jill after t seconds = 4t meters

and total displacement of Jack after t seconds = 2t meters

Initially they were separated by a distance 200 meters

We need to calculate the time,

Using formula of total distance

[tex]2t+4t=200[/tex]

[tex]t=\dfrac{200}{6}[/tex]

[tex]t=33.33\ sec[/tex]

Jill will ran into jack after 33.33 sec.

We need to calculate the distance traveled by Jack in 33.33 seconds

Using formula of distance

[tex]d=v\times t[/tex]

Put the value into the formula

[tex]d=2\times33.33[/tex]

[tex]d = 66.67\ m[/tex]

Hence, Jill will ran into jack after 33.33 sec.

The distance traveled by Jack in 33.33 seconds is 66.67 m.