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a roulette wheel has 38 slots in which the ball can land. two of the slots are green, 18 are red, 18 are black. the ball is equally likely to land in any slot. the roulette wheel is going to be spun twice and the outcome of the two spins are independant.
the probability that it lands on red the first time and black the second time is:
a- 0.2136
b- 0.2244
c- 0.2500
d- 0.5000

Respuesta :

Answer:

The answer is b.)

Step-by-step explanation:

There are 38 slots in which the ball can land .

2 of the slots are green

18 of the slots are red

18 of the slots are black

The wheel is spun twice. The outcome of both the spins are independent of each other.

Therefore the probability, p(ball lands on red the first time and black the second time)

 = p( ball lands on any one of 18 red slots) × p(ball lands on any one of 18 black slots)

   = [tex]\frac{number \hspace{0.1cm} of \hspace{0.1cm} red \hspace{0.1cm} slots }{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} slots} \times\frac{number \hspace{0.1cm} of \hspace{0.1cm} black \hspace{0.1cm} slots }{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} slots} = \frac{18}{38} \times \frac{18}{38} = 0.2244[/tex]

The answer is b.)

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