Answer:
[tex]\frac{1}{3}y+\frac{8}{3}y=\frac{9}{3}y[/tex]
Step-by-step explanation:
As the given expression
[tex]\frac{1}{3}y+\frac{8}{3}y=\frac{9}{3}y[/tex]
Simplifying the left side of the expression
[tex]\frac{1}{3}y+\frac{8}{3}y[/tex]
[tex]\mathrm{Factor\:out\:common\:term\:}y[/tex]
[tex]=y\left(\frac{1}{3}+\frac{8}{3}\right).....A[/tex]
Solving
[tex]\frac{1}{3}+\frac{8}{3}[/tex]
[tex]\mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}[/tex]
[tex]=\frac{1+8}{3}[/tex]
[tex]\mathrm{Add\:the\:numbers:}\:1+8=9[/tex]
[tex]=\frac{9}{3}[/tex]
so the equation A becomes
[tex]=\frac{9}{3}y[/tex]
Therefore,
[tex]\frac{1}{3}y+\frac{8}{3}y=\frac{9}{3}y[/tex]
