C++ a. Write a program that uses the function isPalindrome given in example 6-6 (Palindrome). Test your program on the followinng strings: "madam", "abba", "22", "67876", "444244", and "trymeuemyrt" b. Modify the function isPalindrome of example 6-6 so that when determining weather a string is a palindrome, cases are ignored, that is, uppercase and lowercase letters are considered the same. Example 6-6: bool isPalindrome (string str) { int length = str.Length(); for (int i = 0; i < length / 2; i++) if (str[i] != str[length - 1 - i]; return false; return true; }

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tonb tonb · Answer 1 · 2020-02-22T17:49:03+01:00

Answer:

#include <iostream>

#include <array>

using namespace std;

bool isPalindrome(string str)

{

int length = str.length();

for (int i = 0; i < length / 2; i++)

if (toupper(str[i]) != toupper(str[length - 1 - i]))

return false;

return true;

}

int main()

{

array<string, 6> tests = { "madam", "abba", "22", "67876", "444244", "trymEuemYRT" };

for (auto test : tests) {

cout << test << " is " << (isPalindrome(test) ? "" : "NOT ") << "a palindrome.\n";

}

Explanation:

The toupper() addition forces characters to uppercase, thereby making the comparison case insensitive.