Answer:
They would meet each other at [tex]01 : 24[/tex] PM.
Step-by-step explanation:
- Erik took a trip to see his friend Mike who lives 308 miles away.
- He left his place at 10 AM driving at 70 mph.
- In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph.
As Erik left his house at 10 AM driving at 70 mph and in 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. It means
Erik left his place at 12:00 PM noon.
so, at 12:00 PM Erik had already traveled:
                                   [tex]2\times 70=140\:\:miles[/tex]
Miles left [tex]=308-140=168\:\:miles[/tex]
Let 't' be the time when they meet
so
[tex]70t\:+\:50t\:=168[/tex]
[tex]120t=168[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}120[/tex]
[tex]\frac{120t}{120}=\frac{168}{120}[/tex]
[tex]t=\frac{7}{5}[/tex]
so
[tex]t=\frac{7}{5}=1.4\:\:hours[/tex]
or [tex]1[/tex] hour and [tex]24[/tex] minutes after [tex]12:00[/tex] noon
i.e.
[tex]12\:+\:1.4\:=1\:O'clock\:+\:24\:minutes[/tex]
Therefore, they would meet each other at [tex]01 : 24[/tex] PM.
