Mike ate 1 3 of a bag of peanuts at the game, and on the way home he ate 1 3 of what was left. How much of the bag of peanuts did mike eat on the way home?

Respuesta :

Answer:

[tex]\frac{2}{9}[/tex]

Step-by-step explanation:

Given that

Mike ate = [tex]\frac{1}{3}[/tex] of peanuts bag

And when he is on the way to home he ate the remaining of [tex]\frac{1}{3}[/tex] peanuts bag

So, the remaining peanuts is

= 1 - [tex]\frac{1}{3}[/tex]

= [tex]\frac{2}{3}[/tex]

So, the total number of peanuts he eat on the way to home is

= [tex]\frac{1}{3}\times\frac{2}{3}[/tex]

= [tex]\frac{2}{9}[/tex]

We simply multiplied the remaining and available peanuts bag ratio so that the correct ratio could come