elizabethew03 elizabethew03

23-02-2020
Mathematics

contestada

Whats the answer please

Whats the answer please class=

Respuesta :

jimthompson5910 jimthompson5910

23-02-2020

Answer: Choice D. [tex]\frac{\ln(28)-5}{3}[/tex]

Work Shown:

[tex]e^{3x+5} = 28\\\\\ln\left(e^{3x+5}\right) = \ln(28)\\\\(3x+5)\ln\left(e\right) = \ln(28)\\\\(3x+5)*1 = \ln(28)\\\\3x+5 = \ln(28)\\\\3x = \ln(28)-5\\\\x = \frac{\ln(28)-5}{3}\\\\[/tex]

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