Answer:
The percent ionization is 0,16%
Explanation:
The percent ionization is defined as the number of ions that exist in a substance.
[tex]PI=\frac{[A-]}{[HA]} x100[/tex]
First, we find the [A-] using the ka equation
HA ⇄ [tex]H^{+} + A^{-}[/tex]
[H+] = [A-]
[tex]Ka=\frac{[H+][A-]}{[HA]}\\ \\[/tex]
since the ionization constant is very small we can assume that the final concentration of [HA] is the same
[tex]Ka=\frac{[H+]^{2} }{[HA]} \\\\[/tex]
[tex][H+]=\sqrt[2]{Ka.[HA]} \\\\[/tex]
[tex][H+] =\sqrt{(2,610^{-7} )(0,1)} = 1,61210^{-4}[/tex]
Now we calculate the percent ionization using these values
[tex]PI=\frac{1,61210^{-4} }{0,1} X100[/tex]
PI=0,16%
