The function f(x) is a quadratic function and the zeros of f(x) are -2 and 4. The y-intercept of f(x) is -32. Write the equation of the quadratic polynomial in standard form.

Respuesta :

Answer:

  f(x) = 4x^2 -8x -32

Step-by-step explanation:

If "a" is a zero, then (x -a) is a factor. For some scale factor k, the equation can be written ...

  f(x) = k(x +2)(x -4)

We want f(0) = -32, so ...

  f(0) = -32 = k(0 +2)(0 -4) = -8k

  4 = k . . . . . divide by -8

Then the factored equation is ...

  f(x) = 4(x +2)(x -4)

Multiplying it out gives ...

  f(x) = 4x^2 -8x -32

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