Help please I’m stuck

Step-by-step explanation:
[tex]\because \triangle FGH \sim \triangle DEF.. (given) \\\\
\therefore \frac{DF}{FH} = \frac{DE}{FG}... (csst) \\\\
\therefore \frac{p}{12} = \frac{32}{24} \\ \\ \therefore \: p = \frac{32}{24} \times 12 \\ \\ \therefore \: p = \frac{32}{2} \\ \\ \huge \red{ \boxed{\therefore \: p =16}}[/tex]
Answer: The value of p is 16
Step-by-step explanation:
Triangle FGH is similar to triangle DEF. This means that the ratio of the length of each side of ∆FGH to the length of the corresponding side of ∆DEF is constant. Therefore,
FG/DE = GH/EF = FH/DF
Therefore,
12/p = 16.5/22
Cross multiplying, it becomes
p × 16.5 = 12 × 22
16.5p = 264
Dividing the left hand side and the right hand side of the equation by 16.5, it becomes
16.5p/16.5 = 264/16.5
p = 16