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The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction) is the point at which the terminal ray of angle Theta intersects the unit circle. What are the values for the cosine and cotangent functions for angle Theta? cosine theta = Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, cotangent theta = negative 1 cosine theta = StartFraction StartRoot 2 EndRoot Over 2 EndFraction, cotangent theta = 1 cosine theta = StartFraction StartRoot 2 EndRoot Over 2 EndFraction, cotangent theta = negative one-half cosine theta = Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, cotangent theta = one-half

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Answer:

[tex] \cot(x) = - 1 \: and \: \cos(x) = - \frac{ \sqrt{2} }{2} [/tex]

Step-by-step explanation:

The given point is :

[tex]( - \frac{ \sqrt{2} }{2}, \frac{ \sqrt{2} }{2})[/tex]

This point is in the second quadrant.

This means:

[tex] \cos(x) = - \frac{ \sqrt{2} }{2}, \sin(x) = \frac{ \sqrt{2} }{2})[/tex]

Cotangent is cosine/sine

[tex] \cot(x)=\frac{ \frac{ \sqrt{2} }{2} }{ - \frac{ \sqrt{2} }{2} } = - 1[/tex]

The values for the cosine and cotangent functions for angle theta are -1 and -✓2/2.

How to solve the cosine?

In the information given, the point that was given is (-✓2/2, ✓2/2). It can be deduced that it's in the second quadrant.

Therefore, cos(x) will be -✓2/2

while sin(x) will be -✓2/2.

Therefore, it can be inferred that cos(x) will be 1 based on the division of the values since they're both equal.

In conclusion, the values for the cosine and cotangent functions for angle theta are -1 and -✓2/2.

Learn more about cosine on:

https://brainly.com/question/24305408

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