Two cyclists leave towns 253 kilometers apart at the same time and travel towards each other. One cyclist travels 5km/h faster than the other. If they meet in 5 hours , what is the rate of each cyclist. Please answer ASAP can anyone assist with this I am up against the clock can anyone help. I will give a 5 star and brainiest

Respuesta :

Answer:

The rate of the slower cyclist is

[tex] 22\frac{4}{5}km/h[/tex]

and that of the faster cyclist is

[tex]27 \frac{4}{5}km/h[/tex]

Step-by-step explanation:

We let x be the rate of the slower cyclist

[tex]rate \times time = distance[/tex]

From the question, the distance between the two towns is 253 and the time taken for the two cyclist to meet is 5 hours

so we can write the equation

[tex]5x + 5(x + 5) = 253[/tex]

We simplify to get the value for x

[tex] \implies5x + 5x + 25 = 253[/tex]

[tex]\implies10x = 253 - 25[/tex]

[tex]\implies10x = 228 [/tex]

[tex]\implies x =22 \frac{4}{5} [/tex]

Hence the rate of the slower cyclist is

[tex]22 \frac{4}{5} km/h[/tex]

and that of the rate faster cyclist is

[tex]27 \frac{4}{5}km/h[/tex]