Answer:
29 minutes more
Step-by-step explanation:
Let m represent minutes
changing the statement to algebra, since the second company charges a different rate at night and weekend we have the equation below;
$19.99 + $0.35m > $29.99
Subtract 19.99 from both sides to isolate m and we have;
$19.99 -$19.99 + $0.35 > $29.99 - $19.99
= $0,35m > $10.00
Divide both side by 0.35 to obtain the value of m;
[tex]\frac{0.35m}{0.35}[/tex] > [tex]\frac{10}{0.35}[/tex]
= m > 28.57
m ⩾ 29 minutes
The second company's will be twenty nine minutes or more costlier than the first company
Answer:
[tex]\$0.35n>\$29.99-\$19.99\\\$0.35n>\$10\\n>28.57[/tex]
Approximately:
n≥29
So the number of night and weekend that the second company's plan cost more then the first company's plan are ≥ 29
Step-by-step explanation:
let say n is the numbers of night and weekend that the second company's plan cost more then the first company's plan.
Since second company has $19.99 and $0.35 during nights and weekend and it is grater than the first company which costs $29.99.
According to the above condition, We will get the equation:
[tex]\$19.99+\$0.35n>\$29.99[/tex]
Solving the above equation:
[tex]\$0.35n>\$29.99-\$19.99\\\$0.35n>\$10\\n>28.57[/tex]
Approximately:
n≥29
So the number of night and weekend that the second company's plan cost more then the first company's plan are ≥ 29
