Answer:
-5, 5
Step-by-step explanation:
The line in this problem can be  written in the form
[tex]y=mx+q[/tex] (1)
where:
[tex]m=\frac{2}{3}[/tex] is the slope
q is the y-intercept
We know that the line passes through the point (-2,5), so substituting these values into eq.(1), we find the value of the y-intercept:
[tex]q=y-mx=5-(\frac{2}{3})(-2)=5+\frac{4}{3}=\frac{19}{3}[/tex]
So the equation of the line is
[tex]y=\frac{2}{3}x+\frac{19}{3}[/tex] (2)
Now we know that point A has coordinates
A(x,3)
So by substituting into eq.(2), we find the missing x-coordinate:
[tex]3=\frac{2}{3}x+\frac{19}{3}\\9=2x+19\\x=\frac{9-19}{2}=-5[/tex]
Similarly, point B has coordinates
B(-2,y)
so substituting into eq(2), we find the missing y-coordinate:
[tex]y=\frac{2}{3}(-2)+\frac{19}{3}=5[/tex]