how many molecules of aspirin C9H804 are there in 100.0 MG tablets of aspirin

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anfabba15 anfabba15 · Answer 1 · 2020-02-24T01:36:01+01:00

Answer:

3.34×10³⁰ molecules of C₉H₈O₄

Explanation:

Let's determine the molar mass of aspirin:

C₉H₈O₄ → 12 g/mol . 9 + 1g/mol . 8 + 16g/mol . 4 = 180 g/mol

Let's convert the mass from g to mg → 180 g . 1000 mg/1g = 180000 mg

= 1.8×10⁵ mg

Now, we make a rule of three:

In 1.8×10⁵ mg of aspirin (1 mol) we have 6.02×10²³ molecules

In 100 mg of aspirin, we may have ( 100 . 6.02×10³) / 1.8×10⁵ = 3.34×10³⁰ molecules

Abdulazeez10 Abdulazeez10 · Answer 2 · 2021-12-03T12:50:31+01:00

The number of molecules of aspirin that are in 100.0 mg tablets of aspirin is 3.34 × 10²⁰ molecules

First, we will determine the number of moles of aspirin present in the 100.0 mg tablets of aspirin.

Using the formula

[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass}[/tex]

Molar mass of aspirin = 180.158 g/mol

From the question

Mass of aspirin = 100.0 mg = 0.1 g

∴ Number of moles of aspirin = [tex]\frac{0.1}{180.158}[/tex]

Number of moles of aspirin = 5.55068 × 10⁻⁴ mole

Now, for the number of molecules of aspirin

Using the formula

Number of molecules = Number of moles × Avogadro's constant

∴ Number of molecules of aspirin = 5.55068 × 10⁻⁴ × 6.022 × 10²³

Number of molecules of aspirin = 3.34 × 10²⁰ molecules

Hence, the number of molecules of aspirin that are in 100.0 mg tablets of aspirin is 3.34 × 10²⁰ molecules

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