Respuesta :
779,247 J is the amount of heat released.
Explanation:
The equation that gives the amount of heat supplied is
[tex]E \text { or } Q=m \times c_{A l} \times \Delta T[/tex]
Where,
E or Q – amount of heat supplied
m- mass
[tex]c_{A l}[/tex] - specific heat capacity of Aluminium
[tex]\Delta T[/tex] – temperature variation caused by heat change
The amount of heat energies that causes the temperature to vary [tex]1^{\circ} \mathrm{C}[/tex] or 1 K per kg of the material is known as specific heat capacity (c)
Here, Given data:
[tex]c_{A l}[/tex] – 0.900 J/g.K
To convert gram into kilogram, multiply and divide by [tex]10^{3}[/tex], we get
Specific heat capacity of aluminum = 900 J/kg. K
m – 5.89 kg
[tex]\Delta T=462^{\circ}-315^{\circ}=147^{\circ} \mathrm{C}[/tex]
By substituting the known values in the above equation, we get
[tex]E \text { or } Q=5.89 \times 900 \times 147=779,247 \mathrm{J}[/tex]
Answer: C) -779,000
Explanation: First convert the mass to grams.
m=(5.89 kg)*(1000 g/1 kg)= 5890 g
Then find the change in temperature. It is not necessary to convert the temperature to Kelvin because the change in temperature is the same in both Kelvin and Celsius.
ΔT= (Final - Initial)= 315 °C - 462 °C= -147 °C
Now put these into the heat equation.
q=mcΔT= (5890 g)*(0.900 J/(g*K))*(-147 °C)= -779247 J= -779000 J
