Answer:
Are needed 240 g of granola at 30% nuts and 360 g of granola at 15% nuts
Step-by-step explanation:
Let
x ----> the mass of one type of granola at 30% nuts
y ----> the mass of one type of granola at 15% nuts
Remember that
[tex]30\%=30/100=0.30[/tex]
[tex]15\%=15/100=0.15[/tex]
[tex]21\%=21/100=0.21[/tex]
we know that
The system of linear equations that model this situation is
[tex]x+y=600[/tex] ----> equation A
[tex]0.30x+0.15y=0.21(600)[/tex]
[tex]0.30x+0.15y=126[/tex] ----> equation B
Solve the system of equations by graphing
Remember that the solution is the intersection point both lines
using a graphing tool
the solution is the point (240,360)
see the attached figure
therefore
Are needed 240 g of granola at 30% nuts and 360 g of granola at 15% nuts