I need help on this problem. It is m FEH=126° and m∠EFG=65·

Answer:
∠FEH = 117°
∠EHG = 115°
Step-by-step explanation:
Arc angles add up to 360°.
Arc FEH = 126°, so arc FGH = 234°.
Inscribed angles are half the central angle.
Arc FEH = 126°, so ∠FGH = 63°.
Arc FGH = 234°, so ∠FEH = 117°.
Interior angles of a quadrilateral add up to 360°.
So ∠EHG = 360° − 65° − 63° − 117° = 115°.