Respuesta :
Answer:
x = 541 m
Dt = ?
vi = 12 m/s
vf = 0 (stop)
a = ?
Use vf^2 = vi^2 + 2a(Dx): 0^2 = (12 m/s)^2 + 2a(541 m), a = -144 m^2/s^2, a = -144 m^2/s^2/(1082 m) = -.1331 m/s/s or -.13 m/s/s
Answer:
x = 541 m
Dt = ?
vi = 12 m/s
vf = 0 (stop)
a = ?
Use vf^2 = vi^2 + 2a(Dx): 0^2 = (12 m/s)^2 + 2a(541 m), a = -144 m^2/s^2, a = -144 m^2/s^2/(1082 m) = -.1331 m/s/s or -.13 m/s/s