Many birds can attain very high speeds when diving. Using radar, scientists measured the altitude of a barn swallow in a vertical dive; it dropped 208 m in 3.0 s. The mass of the swallow was estimated to be 0.018 kg, and its cross-section area as 5.6×10−4m2. What was the drag coefficient for this swallow as it dove?

Respuesta :

Answer:

0.109

Explanation:

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The drag coefficient of a sparrow is required.

The drag coefficient is 0.107.

d = Distance = 208 m

t = Time = 3 s

[tex]\rho[/tex] = Density of air = [tex]1.225\ \text{kg/m}^3[/tex]

A = Area = [tex]5.6\times 10^{-4}\ \text{m}^2[/tex]

m = Mass of bird = 0.018 kg

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

c = Drag coefficient

Velocity of the bird

[tex]u=\dfrac{d}{t}=\dfrac{208}{3}\ \text{m/s}[/tex]

The drag force will be equal to the gravitational force.

[tex]mg=\dfrac{1}{2}\rho u^2cA\\\Rightarrow c=\dfrac{2mg}{\rho u^2A}\\\Rightarrow c=\dfrac{2\times 0.018\times 9.81}{1.225\times (\frac{208}{3})^2\times 5.6\times 10^{-4}}\\\Rightarrow c=0.107[/tex]

The drag coefficient is 0.107.

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