Answer:
x=12
Step-by-step explanation:
we know that
If the two chords are equidistant from the center of the circle, then the chords must be congruent.
so
JK=LM
substitute the given values
[tex]4x+37=5(x+5)[/tex]
solve for x
[tex]5x-4x=37-25\\x=12[/tex]